Integrate ∫ sec²(πx) tan^6(πx) dx

Obviously, I'll love you forever if you can show me the steps to this one.
Seriously I appreciate it.

(and that's tangent to the power of 6)

∫ sec²(πx) tan^6(πx) dx ------1
Tanπx = u
Sec^2πx. πdx = du
So for 1 ∫ u^6 du /π
= u^7 /7 π + c
= Tan^7πx /7 π + c
so will you love me now !!!!!!!!!!!

= (tan^7(πx)) / 7π + C

complete steps can be found here: (then click on "Show Steps")
http://www.wolframalpha.com/input/?i=integrate+%28sec%28xpi%29%29%5E2%28tan%28xpi%29%29%5E6+dx

come on guys... You in Calculus and you don't know about this website...

tan^7(πx)/7*π + C

u = tan(pi * x)
du = pi * sec(pi * x)^2 * dx

tan(pi * x)^6 * sec(pi * x)^2 * dx =>
u^6 * (1/pi) * du

Integrate

(1/7) * (1/pi) * u^7 + C =>
(1/(7 * pi)) * u^7 + C =>
(1/(7 * pi)) * tan(pi * x)^7 + C