What is the integral of x/4th root of (x+2)dx

i need the steps and i know the answer is 4/7(x+2)^7/4-8/3(x+2)^3/4 + C

Let u = x + 2
du = dx

∫ (u - 2) / ⁴√(u) du

∫ [u^(3/4) - 2u^(-1/4)] du

(4/7)u^(7/4) - 2(4/3)u^(3/4) + c

(4/7)(x + 2)^(7/4) - (8/3)(x + 2)^(3/4) + c