Here is the problem:
2x+y/ xy-2x ; x=-2, y=4
2(-2) +(4)/ (-2)(4)+-2(-2)
-4+4/-8+4
0/-4
That is the answer I got. I no it's not done yet. Should I write 0 or "no solution"?
Also, does it look like I did the problem right?
I'm failing math right now, so I need to make this perfect.
2x+y/ xy-2x ; x=-2, y=4
2(-2) +(4)/ (-2)(4)+-2(-2)
-4+4/-8+4
0/-4
That is the answer I got. I no it's not done yet. Should I write 0 or "no solution"?
Also, does it look like I did the problem right?
I'm failing math right now, so I need to make this perfect.
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Anything divided INTO 0 is 0. You can easily see why this is true. Take 0 / 10 = x. So 0 / 10 * 10 = x*10 (we can always multiply an equality by the same number). Then 0 = x*10. Only way for that to be true is for x to be 0. We can generalize this, but I hope you get the idea.
Anything divided BY 0 is undefined. You can't divide by 0, because the answer would be infinity (loosely speaking.)
Anything divided BY 0 is undefined. You can't divide by 0, because the answer would be infinity (loosely speaking.)
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If you get 0 divided by ANY number besides 0 itself, the answer is 0. So 0/-4= 0
The answer is no solution when the 0 is in the denominator, ie -4/0, 0/0, pi/0, etc.
Yeah you did the problem right.
The answer is no solution when the 0 is in the denominator, ie -4/0, 0/0, pi/0, etc.
Yeah you did the problem right.
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0 / (-4) = 0 It's only when zero is the denominator, rather than the numerator, that the solution is undefined.
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Answer is 0...............