How do you find the limit as x approaches 1 from the right of e^[3/(1-x)]?
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lets break it down. what happens to 3/(1-x) when x approaches 1 from the right? It approaches 3/infinitely small number. We also know that this infinitely small number is negative, because we're approaching from the right (1-1.000001 will be negative, however small it is). So the expression inside the brackets above will approach negative infinity. Now what does e^-infinity equal? 0. Well, its approaching 0 as x is approaching 1 from the right.
lets break it down. what happens to 3/(1-x) when x approaches 1 from the right? It approaches 3/infinitely small number. We also know that this infinitely small number is negative, because we're approaching from the right (1-1.000001 will be negative, however small it is). So the expression inside the brackets above will approach negative infinity. Now what does e^-infinity equal? 0. Well, its approaching 0 as x is approaching 1 from the right.