f(x) = -1/x
f(x+h) = -1/(x+h)
Please show me how to plug f(x) and f(x+h) into the difference quotient so it can be simplified.
f(x+h) - f(x) / h
(-1/(x+h) - 1/x) / h ======> now what?
f(x+h) = -1/(x+h)
Please show me how to plug f(x) and f(x+h) into the difference quotient so it can be simplified.
f(x+h) - f(x) / h
(-1/(x+h) - 1/x) / h ======> now what?
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you didnt write it correct
f(x) = -1/x
so if you do f(x+h) - f(x)
will be -1/(x+h) - (-1/x)
now this is a fraction so you just have to find a common fraction
easy way is to mutiply the other fraction by x/x or (x+h)/(x+h)
so -1/(x+h)*(x/x)= -x/(x(x+h))
+1/x = (x+h)/(x(x+h))
this means the difference is
-x/(x*(x+h)) + (x+h)/(x*(x+h))
since the denominators are the same we can make them one fraction
(-x + x+h)/ (x*(x+h))
= h/(x*(x+h))
thats how you simplify
if this is a limit problem you then divide by h
and then take the limit
f(x) = -1/x
so if you do f(x+h) - f(x)
will be -1/(x+h) - (-1/x)
now this is a fraction so you just have to find a common fraction
easy way is to mutiply the other fraction by x/x or (x+h)/(x+h)
so -1/(x+h)*(x/x)= -x/(x(x+h))
+1/x = (x+h)/(x(x+h))
this means the difference is
-x/(x*(x+h)) + (x+h)/(x*(x+h))
since the denominators are the same we can make them one fraction
(-x + x+h)/ (x*(x+h))
= h/(x*(x+h))
thats how you simplify
if this is a limit problem you then divide by h
and then take the limit