I for the life of me cant remember how to do this.
Find any intercepts. y^2=x^3-4x There wouldnt be any Y intercepts are there? How do i find the X?
also
y=x^2+x-2
Find any intercepts. y^2=x^3-4x There wouldnt be any Y intercepts are there? How do i find the X?
also
y=x^2+x-2
-
For y-intercepts, put x = 0, then the equation becomes
y² = 0
so there is a y-intercept at x = 0, y = 0.
For x-intercepts, put y = 0, and you get
x³ - 4x = 0
x (x² - 4) = 0
hence x = 0 or x² = 4, i.e. x = ± 2, so 3 x-intercepts.
y² = 0
so there is a y-intercept at x = 0, y = 0.
For x-intercepts, put y = 0, and you get
x³ - 4x = 0
x (x² - 4) = 0
hence x = 0 or x² = 4, i.e. x = ± 2, so 3 x-intercepts.