(x - 1)^3 = y
x - 1 = ³√y
x = 1 + ³√y
x - 1 = ³√y
x = 1 + ³√y
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(x–1)(x–1)(x–1) = y is the same thing as
(x–1)³ = y. Take cube roots of both sides and get
x – 1 = ∛y
x = 1 + ∛y
(x–1)³ = y. Take cube roots of both sides and get
x – 1 = ∛y
x = 1 + ∛y
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(x - 1)³ = y
x - 1 = ³√y
x = 1 + ³√y
x - 1 = ³√y
x = 1 + ³√y