More help with College Algebra
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > More help with College Algebra

More help with College Algebra

[From: ] [author: ] [Date: 11-08-25] [Hit: ]
@Σ-Use y=x^2.The equation tranforms to 25y^2 = 74y - 49.Use the quadratic formula, and solve for y. Then remember y = x^2, so take the positive and nehgative square root.......
How do I solve this?

25x^4=74x^2-49

Thanks!

-
How do I solve this?

25x^4=74x^2-49

this equation is in 'quadratic' form...

25x^4 - 74x^2 + 49 = 0

(25x^2 - 49)(x^2 - 1) = 0
check

both of the binomial factors are the differences of two squares, so...

(5x + 7)(5x - 7)(x + 1)(x - 1) = 0

x = - 7/5 or x = 7/5 or x = - 1 or x = 1

check


-
Use y=x^2.

The equation tranforms to 25y^2 = 74y - 49.

Use the quadratic formula, and solve for y. Then remember y = x^2, so take the positive and nehgative square root.

-
Well. You have to perform a lot of steps. It's not worth it. Just drop out.
1
keywords: help,with,College,Algebra,More,More help with College Algebra
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .