How do you factor the equation 10x^3-3x^2-x

First, since x is a common factor of all three terms, factor it out to get:
10x^3 - 3x^2 - x = x(10x^2 - 3x - 1).

Then, by factoring by grouping, we have:
10x^2 - 3x - 1
= (10x^2 - 5x) + (2x - 1), by re-writing
= 5x(2x - 1) + (2x - 1), by factoring out 5x from the first set of terms
= (5x + 1)(2x - 1), by factoring out 2x - 1.

Therefore:
10x^3 - 3x^2 - x = x(10x^2 - 3x - 1) = x(5x + 1)(2x - 1).

I hope this helps!

First you start off by factoring out an x:
x(10x^2-3x-1) after it is simplified like this you only need to look at the inside. The inside factors to:
(5x+1)(2x-1) now you just bring back your x to the front to get your final answer:
x(5x+1)(2x-1)

10x^3-3x^2-x = 5x^2(2x-1) +x(2x-1) = x(2x-1)(5x+1)

x ( 10 x ² - 3x - 1 )

x ( 5x + 1 ) ( 2x - 1 )

10x³-3x²-x

x(10x²-3x-1)

x(5x+1)(2x-1)