How to Find the indefinite integral of (1/4+x^2)?
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Note : ∫ [ 1 / ( a² + x² ) ] dx = ( 1/a )· tanֿ¹ ( x/a ) ... (1)
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... ∫ [ 1 / ( 4 + x² ) ] dx
= ∫ [ 1 / ( 2² + x² ) ] dx ...... Now Use (1)
= ( 1/2 )· tanֿ¹ ( x/2 ) + C ................................... Ans.
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Happy To Help !
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... ∫ [ 1 / ( 4 + x² ) ] dx
= ∫ [ 1 / ( 2² + x² ) ] dx ...... Now Use (1)
= ( 1/2 )· tanֿ¹ ( x/2 ) + C ................................... Ans.
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Happy To Help !
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I would assume that you know how to find the derivative of a function. So integeration is the opposite. First split the 1/4 and x squared seperately and integrate each part. 1/4 would change to 1/4x and x^2 would change to x^3/3. Put them together and u have 1/4x+x^3/3+c(constant), find the derivative and you will get 1/4+x^2