Twelve students are in in the Saturday morning Driver Education class, 7 boys and 5 girls. If there are 3 students assigned to each car, what is the probability that Maria, Grace, and Tim are all assigned to Mr. K's car?
First answer gets 10 points
First answer gets 10 points
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Jens solution is the same as mine. Simplified, that's a probability 3/660 or a .4545% chance that they're all assigned to the same car.
If those answers aren't right, there may be a part of the question that you're not telling us.
If those answers aren't right, there may be a part of the question that you're not telling us.
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Edit: Yeah, the first one was incorrect, but don't you think it's a bit rash to give a thumb down for that? People are here to help you after all...with what seems to be your homework.
The information that there are seven boys and five girls is a distraction, it doesn't matter at all - because the students that we care about are specifically named, their gender doesn't matter then anymore.
It'll be (1/4)^3 * (3/4)^9 * (3 out of 12)
The information that there are seven boys and five girls is a distraction, it doesn't matter at all - because the students that we care about are specifically named, their gender doesn't matter then anymore.
It'll be (1/4)^3 * (3/4)^9 * (3 out of 12)
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2 out of 5
1 out of 7
1 out of 4
1+1+1= 3
5/7/4= common denominator ( one at the time 5/7 and then 4)
1 out of 7
1 out of 4
1+1+1= 3
5/7/4= common denominator ( one at the time 5/7 and then 4)
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do i have to get it right to get the points?