Physics question, any help would be helpful, Waves!

[From: ] [author: ] [Date: 11-05-24] [Hit: ]

anyway,(where n = harmonic number = 1 ( fundamental ) v = velocity,so f = 450 / (2*0.n= harmonic number,......

the speed of waves travelling along a wire under tension is 450ms-1. if the wire is fixed at ends 0.75m apart, what is the lowest standing wave-frequency that can be heard? (in Hz)

please explain you answer as much as possible...got my final exam in 2 weeks..

the correct answer is 300Hz
:D thanks!!..:)

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lowest standing wave frequency = fundamental frequency = first harmonic
second lowest wave frequency = 2nd harmonic ( or the first overtone)
anyway,
formula

f = nv/2l

(where n = harmonic number = 1 ( fundamental ) v = velocity, and l = length

so f = 450 / (2*0.75) = 300 Hz

also remember that wavelength (lambda) = 2L / n
n= harmonic number, L = length

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