Chemistry Question! (ionic equation)

The net ionic equation for the reaction between aqueous nitric acid and aqueous sodium hydroxide is

HNO3 (aq) + OH- (aq) → NO3 - (aq) + H2O (l)
H+ (aq) + OH- (aq) → H2O (l)
H+ (aq) + HNO3 (aq) + 2OH- (aq) → 2H2O (l) + NO3 - (aq)
HNO3 (aq) + NaOH (aq) → NaNO3 (aq) + H2O (l)
H+ (aq) + Na+ (aq) +OH- (aq) → H2O (l) + Na+ (aq)

The answer is H+ (aq) + OH- (aq) → H2O (l). I was just wondering if someone could explain why that is the answer. Thank You!

Follow the simple three step process for net ionic equations , and you will have no problem in understanding and doing them

Step 1: Write a molecular equation showing states:
HNO3(aq) + NaOH(aq) → NaNO3(aq) + H2O (l)

step 2: Write a full ionic equation by separating all compounds that can dissociate , into ions
H+(aq) + NO3-(aq) + Na+(aq) + OH-(aq) → Na+(aq) + NO3-(aq) + H2O(l)

step 3: Examine the above ionic equation and delete everything that is identical on both sides of →: In this case Na+(aq) and NO3-(aq)
What is left is the net ionic equation:

H+(aq) + OH-(aq) → H2O(l)

This tells you that only the H+ and OH- ions reacted to form water. The other ions , spectator ions , Na+ and NO3- ions did not react with anything . or to form anything
I think that your method of doing net ionic equations is unnecessarily complicated.

each of the other ones that is not has a (aq) which means it could be broken down some more
So HNO3 could be H+ +NO3- and cancel the other side so that is not the net ionic. that goes for all except the last one and and the second the second is right because it cannot be broken down any further on the reactants side and it equals the product.