Write an equation for the line that passes through the coordinates (2,0) and (0,3)

Would it be 3-0=-3/2(0-2)

If not please show work when you tell me the answer. Thanks

First find slope
y2 - y1 / x2 - x1
3 - 0 / 0 - 2
3/-2
Slope is - 3/2
y = mx + c where m is the slope
y = -3/2x + x
Plug in one set of points (2,0)
0 = - 3/2 * 2 + c
0 = - 3 + 3
c = 3
Equation is y = - 3/2x + 3

If you are trying to put it in point slope form
y - y1 = m(x - x1)
Using (2,0)
y - 0 = -3/2(x - 2)

Point slope form is y-y1=m(x-x1)
So (2,0) would be (x1,y1) and (0,3) would be (x2,y2)
No we have to plug in the numbers of x1,y1 into point slope form to get:
y-0=m(x-2).

Now we have to find out what m (slope) is.
To find slope we use rise over run or the formula ((y2-y1)/(x2-x1)). So plugging in the values we found earlier we get:
(3-0)/(0-2)

Which equals: -(3/2)
So now we can go back and plug in -(3/2) into m to get:

y = -3/2(x-2)

Now all we are left with is distributing the -(3/2) to (x-2) to get:

y = -3/2x + 3.

Now we are done!

Thank you for asking!