Given the following balanced equation, calculate the volume

Given the following balanced equation, calculate the volume of 0.278 M NaI that would be needed to react with all of the Hg2+ ion from 10.51 mL of a 0.168 M Hg(NO3)2 solution.

2NaI(aq) + Hg(NO3)2(aq) HgI2(s) + 2NaNO3(aq)

I'm not sure where to begin with this one. Any help would be greatly appreciated.

Thanks in advance.

2 NaI + Hg(NO3)2 → HgI2 + 2 NaNO3

(10.51 mL) x ( 0.168 M Hg(NO3)2) x (2/1) / ( 0.278 M NaI) = 12.7 mL NaI