What mass of CO2 would be produced during a combustion analysis of 0.40267g of ephedrine?
Answer in units of g.
I don't know the balanced equation D:
Answer in units of g.
I don't know the balanced equation D:
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here is your equation :
4 C10H15NO + 57 O2 = 40 CO2 + 30 H2O + 4 NO2
molar mass of ephedrine is 165.23 g / mole
so moles in the sample = .40267 / 165.23 = 0.002437 moles
ratio if ephedrine to CO2 is 10 : 1 so moles of CO2 produced = 0.024370 moles
or = 0.024370 x 44 g = 1.072 g of CO2
4 C10H15NO + 57 O2 = 40 CO2 + 30 H2O + 4 NO2
molar mass of ephedrine is 165.23 g / mole
so moles in the sample = .40267 / 165.23 = 0.002437 moles
ratio if ephedrine to CO2 is 10 : 1 so moles of CO2 produced = 0.024370 moles
or = 0.024370 x 44 g = 1.072 g of CO2