An aqueous solution 4.68% NaOCl by mass. Assume a density of 1.02 g/mL. What's the molarity

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An aqueous solution 4.68% NaOCl by mass. Assume a density of 1.02 g/mL. What's the molarity

[From: ] [author: ] [Date: 11-10-09] [Hit: ]

47.736 / 70 = 0.Molarity = 0.6819 moles / 1 L = 0.......

Molarity = moles solute / volume solution

lets assume you have 1 Liter of solution, to make things easier.

1L = 1000 mL

1000mL x (1.02g/1mL) = Total grams of soluute. = 1020g solute

but since only 4.68% of it s NaClO, 4.68% x 1020 = 47.736 grams NaClO in 1 liter.

You need moles of NaClO, not grams, so divde 47.736 by the molecular mass, which is 70g
47.736 / 70 = 0.6819 Moles

Molarity = 0.6819 moles / 1 L = 0.6819M

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