Calculate the change in heat when 23.95 grams of water vapor (steam) at 100 degrees celsius condenses...
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Calculate the change in heat when 23.95 grams of water vapor (steam) at 100 degrees celsius condenses...

[From: ] [author: ] [Date: 11-10-08] [Hit: ]
Specific heat of water is 4.184 J/g/°C.1..........
Calculate the change in heat when 23.95 grams of water vapor (steam) at 100 degrees celsius condenses to liquid water and then cools to 1.00 degrees celsius. =________ joules

Thank you for any help you can give me I appreciate it! I have been shown it once on a similar kind of problem, but can't get it for this one.

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Latent Heat of Vaporisation/Condensation is 2,260J/g.
Specific heat of water is 4.184 J/g/°C.

1....To condense the steam.

mcΔT = Q .
23.95g x 2,260J/g = -54,127 (Joules of heat released).

2...To cool the water to 1.0°C

mcΔT = Q.
23.95g x 4.184J/g/°C x 99°C ΔT = -9920.5 (Joules of heat released).

Total heat released = -54,127J + -9,920.5L = -64,047.5 Joules of heat released
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