For the following reaction, 3.26 grams of ethylene (C2H4) are mixed with excess hydrogen gas. The reaction yields 2.36 grams of ethane (C2H6).
hydrogen (g) + ethylene (C2H4) (g) --> ethane (C2H6) (g)
I don't know how to set it up or solve it! Thanks in advance for any help or answers!
hydrogen (g) + ethylene (C2H4) (g) --> ethane (C2H6) (g)
I don't know how to set it up or solve it! Thanks in advance for any help or answers!
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You are mixed up! All of a sudden you mention AgCl.
The equation is balanced , so the ratio is 1 to 1 . H2 + C2H4 --> C2H6
Moles of C2H4 = 3.26 / 28 = 0.116
Moles of C2H6 = 2.36 / 30 = 0.0787
The C2H4 is in excess.
Grams of C2H6 prodiced = 0.0787 x 30 m= 3.49g
The equation is balanced , so the ratio is 1 to 1 . H2 + C2H4 --> C2H6
Moles of C2H4 = 3.26 / 28 = 0.116
Moles of C2H6 = 2.36 / 30 = 0.0787
The C2H4 is in excess.
Grams of C2H6 prodiced = 0.0787 x 30 m= 3.49g