In order to synthesise 3-bromonitrobenzene from benzene, which of the
following sets of conditions are necessary?
a. i) H2SO4/HNO3 (heat is necessary) followed by ii) Br2/FeBr3 (further heat required)
b. i) Br2/FeBr3 followed by ii) H2SO4/HNO3
c. i) Br2 in CCl4 followed by ii) H2SO4/HNO3 (heat required)
d. i) H2SO4/HNO3 followed by ii) Br2/FeBr3 (heat required)
e. i) H2SO4/HNO3 followed by ii) Br2/FeBr3
Any help would be appreciated, I really I no idea how to do these. Thankyou!!
following sets of conditions are necessary?
a. i) H2SO4/HNO3 (heat is necessary) followed by ii) Br2/FeBr3 (further heat required)
b. i) Br2/FeBr3 followed by ii) H2SO4/HNO3
c. i) Br2 in CCl4 followed by ii) H2SO4/HNO3 (heat required)
d. i) H2SO4/HNO3 followed by ii) Br2/FeBr3 (heat required)
e. i) H2SO4/HNO3 followed by ii) Br2/FeBr3
Any help would be appreciated, I really I no idea how to do these. Thankyou!!
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well first you got to do Nitration. So to introduce the NO2 to the ring. You introduce this first cause it will determine the orientation. Which is meta (1,3). Next with then be halogenation.
So you can eliminate b and c and a. Although a nitration process it has high temp which it not allowed since it can substitute more than just one place in the ring. So its down to d or e. But i would say its d. Since Its hard to introduce a halogen group directly to the benzene ring. Other methods of adding can proceed via diazonium reaction then sandmayer.
hopefully this can help you.hehe
So you can eliminate b and c and a. Although a nitration process it has high temp which it not allowed since it can substitute more than just one place in the ring. So its down to d or e. But i would say its d. Since Its hard to introduce a halogen group directly to the benzene ring. Other methods of adding can proceed via diazonium reaction then sandmayer.
hopefully this can help you.hehe