2 Al (s) + 6 HCl (aq) ----------> 2 AlCl3 (aq) + 3 H2 (g)
What is the mass of Al (s) needed to produce 508.8 mL of H2 gas at STP?? Any help with this question would be really appreciated!!!
What is the mass of Al (s) needed to produce 508.8 mL of H2 gas at STP?? Any help with this question would be really appreciated!!!
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2 Al + 6 HCl → 2 AlCl3 + 3 H2
(0.5088 L) / (22.414 L/mol) x (2/3) x (26.9815 g Al/mol) = 0.4083 g Al
(0.5088 L) / (22.414 L/mol) x (2/3) x (26.9815 g Al/mol) = 0.4083 g Al