Not really. The Richter scale is defined in terms of earthquake wave amplitudes.
However, if you convert Richter values to energy (an imprecise conversion), then you can compare that to supernova energy. Supernovas vary in energy level, but a typical supernova would measure roughly 26.
However, if you convert Richter values to energy (an imprecise conversion), then you can compare that to supernova energy. Supernovas vary in energy level, but a typical supernova would measure roughly 26.
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The Richter scale measures earthquakes, not explosions, but even if it did measure novas, the numbers are a bit inadequate given how violent and how much more massive than Earth stars are. Example--the Sun, which is much too small to explode, is 330,000 times more massive than Earth, and earthquakes typically involve less than 0.1% of the mass of the Earth.
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Only if you can answer the following questions:
How far is Chicago from Tokyo, in degrees Celsius?
If Jill is twice as old as Jane, and Jane is 14 years old, how many miles is Jane?
How many ounces are in a lightyear?
How far is Chicago from Tokyo, in degrees Celsius?
If Jill is twice as old as Jane, and Jane is 14 years old, how many miles is Jane?
How many ounces are in a lightyear?
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The Richter scale is used to measure the intensity and strength of earthquakes.
Supernovas are not earthquakes.
So...no.
Supernovas are not earthquakes.
So...no.
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I suppose you could but Richter has to do with earth quakes and a Chevy Super Nova deals with MPG - miles per gallon and RPM's, I suggest you rethink this question