Calculate Current given this circuit
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Calculate Current given this circuit

[From: ] [author: ] [Date: 13-09-25] [Hit: ]
They OPPOSE each other.So instead of summing e1 and e2, what would you do instead? I agree summing the resistances.......
I don't want the answer, just a nudge in the right direction. I know that current I=ε/R(eq). Why wouldn't I= (ε1+ε2)/(R1+R2+R3)?

Consider the circuit in the figure below with resistors R1 = 2,400 Ω, R2 = 4,400 Ω, and R3 = 1,900 Ω, and batteries with emfs 1 = 6.7 V and 2 = 1.4 V. What is the magnitude of the current in the circuit?


Image of the circuit is at the following link:

http://tinypic.com/r/2ltpwrn/5

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You are close. If ε1 or ε2 were reversed, then you would be right. They would be working together.

Then:
I = (ε1+ε2) / (R1+R2+R3)

But the two +'s are on the same side, which means they are opposing each other. You have to make a small change to your formula. (I = 0.609A).

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Look closely at the batteries in your pic. They OPPOSE each other. So instead of summing e1 and e2, what would you do instead? I agree summing the resistances.
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