If the curve y= x(x+2)(x-3) is reflected on the y-axis, then what is the new equation of the curve? The answer is y=x(-x+2)(x+3) but i don't know how to do it. Please provide a step-by-step solution ASAP!!! Thanx
-
y = f(x) , reflected about y-axis => y = f(-x)
y = x(x + 2)(x - 3)
y = x(x^2 - x - 6)
y = x^3 - x^2 - 6x
y = f(-x):
y = (-x)^3 - (-x)^2 - 6(-x)
y = -x^3 - x^2 + 6x
y = -x(x^2 + x - 6)
y = -x(x - 2) (x + 3)
or:
y = x(-x + 2)(x + 3)
y = x(x + 2)(x - 3)
y = x(x^2 - x - 6)
y = x^3 - x^2 - 6x
y = f(-x):
y = (-x)^3 - (-x)^2 - 6(-x)
y = -x^3 - x^2 + 6x
y = -x(x^2 + x - 6)
y = -x(x - 2) (x + 3)
or:
y = x(-x + 2)(x + 3)
-
The reflection of y=f(x) is y=f(-x) so you could write the answer as
y = -x(-x+2)(-x-3)
However it would be simpler to write
y = x(-x+2)(x+3)
If you aren't sure why that last step is ok, you could say that you are multiplying the leading x factor by -1 and dividing the -x-3 factor by -1.
y = -x(-x+2)(-x-3)
However it would be simpler to write
y = x(-x+2)(x+3)
If you aren't sure why that last step is ok, you could say that you are multiplying the leading x factor by -1 and dividing the -x-3 factor by -1.
-
On reflection in the y axis the point (x,y) becomes (-x,y) so the curve y = f(x) becomes the curve
y = f(-x).You simply replace x by -x. In your case you get y = -x (-x +2) (-x -3) = x( -x +2) ( x+3).
y = f(-x).You simply replace x by -x. In your case you get y = -x (-x +2) (-x -3) = x( -x +2) ( x+3).