A house at the bottom of a hill is fed by a full tank of water Lw=58 m deep and connected to the house by a pipe that is Lp=95 m long at an angle of = 52º from the horizontal.
Determine the gauge pressure at the house.
Can someone explain how to do this, I keep getting it wrong.
Determine the gauge pressure at the house.
Can someone explain how to do this, I keep getting it wrong.
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The gauge pressure is given by the equation P=ρgh where p=1000kg/m^3
I am also assuming that since no diagram is given, the house is on the bottom of the hill.
To find the height of the hill use trigonometry. Since the height is opposite the pipe, we see
h=Lpsinθ=(95)sin(52)=74.9m
Then to find total height just add the 5.8 m from the tank
74.9m+5.8m=80.7 m
Now plug in values:
P=ρgh
=(1000)(9.8)(80.7)
=7.9e5 N/m^2
I am also assuming that since no diagram is given, the house is on the bottom of the hill.
To find the height of the hill use trigonometry. Since the height is opposite the pipe, we see
h=Lpsinθ=(95)sin(52)=74.9m
Then to find total height just add the 5.8 m from the tank
74.9m+5.8m=80.7 m
Now plug in values:
P=ρgh
=(1000)(9.8)(80.7)
=7.9e5 N/m^2