A mixture of helium and neon gases is held in a container at 1.2 atmospheres. If the mixture contains twice as many helium atoms as neon atoms, what is the partial pressure of helium?
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Partial Pressure of He = (Moles of He/Total Moles) * Total Pressure
If there are twice as many helium atoms compared to neon atoms then there is twice the moles of helium compared to neon. Thus a 2:1 molar ratio tells you that 2/3 of the mixture is helium. Therefore:
Partial Pressure of He = 2/3 * 1.2
Partial Pressure of He = 0.8 atmospheres.
If there are twice as many helium atoms compared to neon atoms then there is twice the moles of helium compared to neon. Thus a 2:1 molar ratio tells you that 2/3 of the mixture is helium. Therefore:
Partial Pressure of He = 2/3 * 1.2
Partial Pressure of He = 0.8 atmospheres.