A person of mass 70 kg rides on a Ferris wheel whose radius is 4 m.

The person's speed is constant at 0.3 m/s. What is the magnitude of the rate of change of the momentum of the person at the top position?

As the tangential speed is constant there is no ∆mom due to this .. the only change in mom is due to the centripetal acceleration .. a = v²/r

Rate of change of mom towards centre = (m x dv)/dt .. dv = change in vel towards centre and dv/dt = centripetal accel (a)
Rate of change of mom = (m x a) = m.v²/r ..

= 70kg x (0.30m/s)² / 4.0m .. .. ►1.58kg.m/s²