Flow rate/gauge pressure
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Flow rate/gauge pressure

[From: ] [author: ] [Date: 12-06-29] [Hit: ]
taking the fluid to be ideal.Im guessing I just use Bernoullis here?but how do roh and height and all that play in?=/Any ideas on how to solve this? Thanks!h1 = h2 so they cancel.......
Hi, I need help with this problem.

Problem: A horizontal water main with a cross-sectional area of 220 cm2 necks down to a pipe of area 50 cm2. Meters mounted in the flow on each side of the transition coupling show a change in gauge pressure of 85 kPa. Determine the flow rate through the system, taking the fluid to be ideal.

I'm guessing I just use Bernoulli's here?

but how do roh and height and all that play in? =/ Any ideas on how to solve this? Thanks!

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Area 1 x v1 = Area 2 x v2 is one equation Get v1 in terms of v2

P1 + rho g h1 + 1/2 rho v1^2 = P2 + rho g h2 + 1/2 rho v2^2

h1 = h2 so they cancel. P1 - P2 = 85000 Pa

Plug in v1 in terms of v2 and solve for v2, then calculate Area 2 x v2 to get the flow rate. For water rho = 1000 kg/m^2
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