If you throw a ball normally you can't throw it with much force.
To get the maximum speed, you extend your arm out back and then throw.
is it because the muscles in our arms contract or does it have to do with objects having more potential energy at greater heights?
To get the maximum speed, you extend your arm out back and then throw.
is it because the muscles in our arms contract or does it have to do with objects having more potential energy at greater heights?
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I'd like to add to 2 of the answers hopefully directly above me.
I think we also need to include torque and force in this discussion as well.
Torque = length X force. Let's say we exert 100N of force with an arm that is 1 ft long, we'd have 100 ft-N of torque.
Now let's say our arm is 2 ft long with the same force, 100N X 2 ft = 200 N-ft of torque.
Have you ever seen those new dog toys that owners have to throw tennis balls further for their dogs? It's like a scoop on the end of a handle? Exact same principle. It is adding length to your arm with gives it more torque.
I think we also need to include torque and force in this discussion as well.
Torque = length X force. Let's say we exert 100N of force with an arm that is 1 ft long, we'd have 100 ft-N of torque.
Now let's say our arm is 2 ft long with the same force, 100N X 2 ft = 200 N-ft of torque.
Have you ever seen those new dog toys that owners have to throw tennis balls further for their dogs? It's like a scoop on the end of a handle? Exact same principle. It is adding length to your arm with gives it more torque.
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your arm can only provide so much force. the speed of the ball is a product of the force you apply time the time you apply if for (F x t). by pulling back your arm further, you can apply the force for a longer time, thus give the ball a faster speed. Full equation set below:
f x t = m x v
f is the force you apply, t is the time you apply it, mass is the mass of the object you are throwing, and v is the velocity (speed). If you solve for speed you will see the answer.
f x t = m x v
f is the force you apply, t is the time you apply it, mass is the mass of the object you are throwing, and v is the velocity (speed). If you solve for speed you will see the answer.
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This is a pretty simple question... It has to do with WORK! ... Work is force x distance. you can throw a ball faster because you have increased the DISTANCE that you are applying the force.
Work is measured in joules. YUP work is ENERGY ^_^. So Force x distance = 1/2 MV^2
So what a joule? joules are (kg·m^2)/s^2
So let's salve this algebraically.
fd=(1/2)mv^2
2fd=mv^2
(2fd)/m=v^2
√((2fd)/m)=v
Work is measured in joules. YUP work is ENERGY ^_^. So Force x distance = 1/2 MV^2
So what a joule? joules are (kg·m^2)/s^2
So let's salve this algebraically.
fd=(1/2)mv^2
2fd=mv^2
(2fd)/m=v^2
√((2fd)/m)=v
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it's because
mgh=1/2mv^2 (where h is the displacement of the arm)
h is directly proportional to v^2
so more the displacement of the arm more is the velocity
mgh=1/2mv^2 (where h is the displacement of the arm)
h is directly proportional to v^2
so more the displacement of the arm more is the velocity
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Your arm builds more speed.