i need the answer asap plz !
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1/(x - x^2) = 1/[x(1 - x)] = A/x + B/(1 - x)
1 = A(1 - x) + Bx
If x = 1: 1 = B
If x = 0: 1 = A
∫ dx/x + ∫ dx/(1 - x) = ln |x| - ln |1 - x| = ln |x/(1 - x)|
1 = A(1 - x) + Bx
If x = 1: 1 = B
If x = 0: 1 = A
∫ dx/x + ∫ dx/(1 - x) = ln |x| - ln |1 - x| = ln |x/(1 - x)|