Integrated Algebra Question
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Integrated Algebra Question

[From: ] [author: ] [Date: 12-06-14] [Hit: ]
so the numbers must be 7, 9,......
The sum of three consecutive odd integers is 18 less than five times the middle number. Find the three integers. Only and algebraic solution can solve the answer.

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Consecutive odd integers differ by 2; call them x, x+2, and x+4.

From the problem, we know that x + x+2 + x+4 = 5(x+2) - 18; solve for x:
3x + 6 = 5x + 10 - 18
3x + 6 = 5x - 8
6 = 2x - 8
14 = 2x
x = 7, so the numbers must be 7, 9, and 11
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