I'm having trouble with these word problems and they will be on my final.
Can someone help and explain? My teacher doesn't explain it that well.
1. The perimeter of a rectangle is 116. The length is 16 cm greater than the width. Find the width and length.
2. At a club, 225 tickets were sold. Adult tickets = $6 Children tickets = 5.25. In all, $1264.50 was made. How many of each kind of ticket sold?
3. One number is 2 more than three time another. Their sum is 26. Find the numbers.
4. The sum of a two digit number is 7. When the digits are reversed the number is increased by 27. Find the number.
I get the basic concepts for some of these but I just don't get how it works.
Thanks, I will choose best answer!
Can someone help and explain? My teacher doesn't explain it that well.
1. The perimeter of a rectangle is 116. The length is 16 cm greater than the width. Find the width and length.
2. At a club, 225 tickets were sold. Adult tickets = $6 Children tickets = 5.25. In all, $1264.50 was made. How many of each kind of ticket sold?
3. One number is 2 more than three time another. Their sum is 26. Find the numbers.
4. The sum of a two digit number is 7. When the digits are reversed the number is increased by 27. Find the number.
I get the basic concepts for some of these but I just don't get how it works.
Thanks, I will choose best answer!
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1) Considering x the width and y the length, then 2x+2y = 116 ==> x+ y = 58
And y = x+ 16 .... then x + x+ 16 = 58 ==> x = 21 and y = 37 ... width = 21cm and length = 37cm. OK!
2) Considering x the adult ticket and y the children ticket , then x+ y = 225
And 6x + 5.25y = 1,264.50... from the first equation y = 225 -x
The put in the second equation 6x +5.25(225 -x) = 1,264.50 ==> x = 111 and y = 114 OK!
3) Considering the numbers x and y we have... x+y = 26 and y = 3x +2
Put it in the first equation... x+ 3x + 2 = 26 ==> x =6 and y = 20 OK!
4) Considering x and y the digits we have x+ y = 7 .... Considering the number xy = 10x + y
The reversed is yx = 10y + x .... then 10y + x = 10x +y + 27 .... from the first equation y = 7-x
Then 10(7-x) + x = 10x + 7-x + 27 ==> x= 2 and y =5 OK!
And y = x+ 16 .... then x + x+ 16 = 58 ==> x = 21 and y = 37 ... width = 21cm and length = 37cm. OK!
2) Considering x the adult ticket and y the children ticket , then x+ y = 225
And 6x + 5.25y = 1,264.50... from the first equation y = 225 -x
The put in the second equation 6x +5.25(225 -x) = 1,264.50 ==> x = 111 and y = 114 OK!
3) Considering the numbers x and y we have... x+y = 26 and y = 3x +2
Put it in the first equation... x+ 3x + 2 = 26 ==> x =6 and y = 20 OK!
4) Considering x and y the digits we have x+ y = 7 .... Considering the number xy = 10x + y
The reversed is yx = 10y + x .... then 10y + x = 10x +y + 27 .... from the first equation y = 7-x
Then 10(7-x) + x = 10x + 7-x + 27 ==> x= 2 and y =5 OK!