Solve 3squareroot24x= 3^3squarerootx+2
Solve x-3=(x+3)^1/2
Solve -3+squareroot4x-3<=8
Thank you! Show work please.
Solve x-3=(x+3)^1/2
Solve -3+squareroot4x-3<=8
Thank you! Show work please.
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The first one is transcendental, unless I am reading it incorrectly
The second one:
square both sides: (x-3)^2 = x+3, x^2 - 7x + 6 = (x-6)(x-1) = 0, or x = 6, 1
The third one:
add 3 to both sides: (4x-3)^(1/2) <= 11
square both sides: 4x-3 <= 121
add 3 to both sides: 4x <= 124 or x <= 124/4 = 31
The second one:
square both sides: (x-3)^2 = x+3, x^2 - 7x + 6 = (x-6)(x-1) = 0, or x = 6, 1
The third one:
add 3 to both sides: (4x-3)^(1/2) <= 11
square both sides: 4x-3 <= 121
add 3 to both sides: 4x <= 124 or x <= 124/4 = 31