If z = x + ib, where x and y are real, find the values of x and y when

3z/(1-j) + 3z/j = 4/(3-j)

http://www.wolframalpha.com/input/?i=3z%…

Can someone show me the steps, I'm getting lost in the algebra

3zj(3-j)+3z(1-j)(3-j) = 4j(1-j)
9jz+3z+3z(2-4j) = 4j+4
9jz+3z+6z-12jz = 4j+4
-3jz+9z = 4j+4
3z(3-j) = 4(1+j)
z = 4(1+j)/3(3-j)
z = 4(1+j)/3(3-j) * (3+j)/(3+j)
z = 4(3+4j-1)/30 = 2(2+4j)/15
z = 4/15 + 8j/15
x = 4/15, y = 8/15