The 4 consecutive integers immediately lower than 81,and 4 conse.inte.higher than 81,are written...!!

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The 4 consecutive integers immediately lower than 81,and 4 conse.inte.higher than 81,are written...!!

[From: ] [author: ] [Date: 12-05-23] [Hit: ]

.answer is 9-1) As given, four consecutive integers lower than 81 are (81-1), (81-2),Similarly higher of 81 are: (81+1) (81+2),[There are more divisors for this; however I have limited to only value 9,......

Written down and added together.This sum is divisible by which num????explain me plz ..answer is 9

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1) As given, four consecutive integers lower than 81 are (81-1), (81-2), (81-3) & (81-4)
Similarly higher of 81 are: (81+1) (81+2), (81+3) & (81+4)

2) Hence the sum of these 8 numbers are: 81 x 8 = 9 x 9 x 8

Thus it is divisible by 9

[There are more divisors for this; however I have limited to only value 9, as per your requirement]

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