Did I solve this correctly? Serious answers only
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Did I solve this correctly? Serious answers only

[From: ] [author: ] [Date: 12-05-23] [Hit: ]
Thanks.-The directions say to solve each equation by graphing.Heres a graph.http://www.algebra.According to this graph,......
No silly answers like "yup you're good" or "yep you did it right :D" just because you want points, I want people who are good at math to determine if I did it right or not. Thanks.

Solve each equation by graphing.

6x + 2y = 12
y = 3x

I solved it like this:

6x + 2(3x = 12)
6x + (6x = 12)
12x = 12
x = 1
y = 3

So it's (1,3)

Is that correct? Thanks.

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The directions say to "solve each equation by graphing."


Here's a graph.

http://www.algebra.com/algebra/homework/…

According to this graph, your answer is correct!
("yep you did it right :D").

-
Your solution is correct, but your notation is faulty. It should appear like this:
6x + 2(3x) = 12
6x + 6x = 12
12x = 12
x = 1, so y = 3(1) = 3

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Correct answer, but the parentheses are wrong.
6x + 2(3x) = 12
6x + 6x = 12
12x = 12
x = 1

y = 3(1) = 3

-
It's correct :) I just don't understand why did you put brackets like that.
Check: 6x1 + 2x3 = 12
6 + 6 = 12
12 = 12

-
6x + 2y = 12 ..................1
y = 3x............................2

1 into 2 we have

6x+2(3x)=12
6x+6x=12
x=1
sub into

y=3(1)
=3

-
6x+2*3x=12

6x=12

x=2
1
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