Problem:
[1 2]
[3 1]
[5 3]
X
[2 4 5]
[0 -1 1]
My Answer:
1x2+2x1=4
3x4+1x-1=12
5x5+3x1=28
[1 2]
[3 1]
[5 3]
X
[2 4 5]
[0 -1 1]
My Answer:
1x2+2x1=4
3x4+1x-1=12
5x5+3x1=28
-
The first term should be
1(2) + 2(0) = 2
There is a minor mistake with the middle term
3(4) + 1(-1) = 12 - 1 = 11
I agree with the last term
1(2) + 2(0) = 2
There is a minor mistake with the middle term
3(4) + 1(-1) = 12 - 1 = 11
I agree with the last term
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I am sorry! you are not quite correct
first matrix is a3X2 and the other is a 2X3 since the "inside" numbers are the same you can multiply and the resulting matrix will be a 3X3
1x2+2x0 1x4+2(-1) 1x5+2x1 2 2 7
3x2+1x0 3x4+1(-1) 3x5+1.1 6 11 16
5x2+3x0 5x4+3x(-1) 5x5+3x1 = 10 17 28
first matrix is a3X2 and the other is a 2X3 since the "inside" numbers are the same you can multiply and the resulting matrix will be a 3X3
1x2+2x0 1x4+2(-1) 1x5+2x1 2 2 7
3x2+1x0 3x4+1(-1) 3x5+1.1 6 11 16
5x2+3x0 5x4+3x(-1) 5x5+3x1 = 10 17 28
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You Did It Correctly