Solving log equation help!!

log (base 7) 3x^2 - log (base 7) 9 = log (base 7) 27

the answer is 9, -9

let log be log to base 7
log [ 3x² / 9 ] = log 27
3x² / 9 = 27
3x² = 243
x² = 81
x = ± 9

Thank you----pleased to help.

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log[7] 3x^2 - log[7] 9 = log[7] 27.............baby step by baby step:

log[7] (3x^2/9) = log[7] (x^2/3) = log[7] 27

x^2/3 = 27

x^2 = 81

x = ± 9

log (3x^2) = log (27) + log (9)
log (3x^2) = log (27 x 9)
log (3x^2) = log (243)

3x^2 = 243
x^2 = 81
x = (+/-) 9