How do I find how the products of a chemical equation

How do I find how the products of a chemical equation?
I need help all i need to find is the product(s) and balance the equation. I have a bunch of problems to do but i just need help getting started. Please help?

Here is an example from my sheet, please help?

manganese(II) chloride + aluminum fluoride


Thanks

3 MnCl2 (s) + 2 AlF3 (s) ------> 3 MnF2 (s) + 2 AlCl3 (s)

"s" stands for solid state.

Hannah, it's not AlF, but AlF3.

I know that there is a fish out of water when i see a question like "How do I find how [sic] the products of a chemical equation?"
The simple answer is all chemicals on the right side of the arrow are products.
You go on to completely change the question into one asking how you complete the chemical reaction, given only reactants. I must conclude that either ignorance or stupidity are involved in your lack of clear thinking, if not both.
They say that once you have mastered the terminology of a discipline, you have 80% - 90% of it learned. Given that you don't seem to understand what is (and is not) a chemical equation, then you are in trouble.
Reactions between two solids is extremely rare. Reactions usually happen in the gas phase, in the liquid phase and also on the surface of solids with liquids (solvents or solutes) or gasses and other species found on the surfaces.
You not only do not know what a chemical equation is, but apparently are unable to encode the chemicals as chemical symbols.
1. Figure out what the formulas are for manganese(II) chloride and AlFx
2. Give enough information to enable us to help you. I suspect that the reactions that you completely failed to understand are the mixing of two aqueous solutions;
eg.: MnClx(aq) + AlFy(aq) → ?
3. IF these are simple precipitation reactions, what you need to do is look up the solubilities to determine whether the "cross-products" are soluble; eg.: MnFx and AlCly
In order to do that you need to balance the equations
eg.:aMnClx(aq) + bAlFy(aq) → cMnFx + dAlCly solving for the integers a,b,c & d (after you have figured out the integers x & y which if you had any idea what was going on would be trivial (hint Mn(II) indicates the formal oxidation state (charge) of the Mn species).

MnCl2 (2 is a subscript) + AlF -----> MnF +ClAl (I think)

It is definetly a double replacement, which means they will switch partners.

I think for the balanced equation it would be

MnCl2 (sub) + 2 AlF --> MnF2 (sub) + 2 ClAl