A student wants to make an aqueous .25 M solution of SrI2. How many grams of solute would the student dissolve in 355mL of water?
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(0.355 L) x (0.25 mol/L) x (341.4299 g SrI2/mol) = 30 g SrI2
But the correct way to make a .25 M solution is to add however much water is necessary to have 355mL of solution.
By adding the solute to 355mL of water you've made a .25 m solution, which is similar, but technically a different thing.
But the correct way to make a .25 M solution is to add however much water is necessary to have 355mL of solution.
By adding the solute to 355mL of water you've made a .25 m solution, which is similar, but technically a different thing.