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I need chemistry Help!

[From: ] [author: ] [Date: 12-05-23] [Hit: ]
But the correct way to make a .25 M solution is to add however much water is necessary to have 355mL of solution.By adding the solute to 355mL of water youve made a .25 m solution, which is similar, but technically a different thing.......
A student wants to make an aqueous .25 M solution of SrI2. How many grams of solute would the student dissolve in 355mL of water?

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(0.355 L) x (0.25 mol/L) x (341.4299 g SrI2/mol) = 30 g SrI2

But the correct way to make a .25 M solution is to add however much water is necessary to have 355mL of solution.

By adding the solute to 355mL of water you've made a .25 m solution, which is similar, but technically a different thing.
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