Help with Matrix Multiplication Math
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Help with Matrix Multiplication Math

[From: ] [author: ] [Date: 12-05-23] [Hit: ]
so,when you see the inside numbers (as here are the 3and 3) to be the same,[1*2 + 3*1 + 2*3] = 2+3+6 = [12]-First matrix is 1*3 and second is 3*1.You take the outer two so the answer will be 1*1.......
[1 3 2] x

[1]
[1]
[3]

I'm confused on how to do this. Could someone please explain it to me? Also, on the second bracket, it's supposed to be just one big bracket, not 3 separate ones.

Thanks!

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First of all you must know that in order to multiply matrices the columns of the first=rows of the other

Number of rows is written first and then the number of columns

so, the first matrix is a 1X3 and the second a 3X1

when you see the "inside" numbers (as here are the 3 and 3) to be the same, it means you CAN multiply and the resulting matrix will be the "outside" numbers like here 1X1

To multiply : take the first matrix and turn it to the right by 90 degrees so that it becomes 1
3
2

put this on the left before the other like this 1 X 1
3 1
2 3 now multiply each element with the corresponding one and add

1X1+3X1+2X3=10

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The row matrix post multiplied by the column matrix yields the 1x1 matrix:
[1*2 + 3*1 + 2*3] = 2+3+6 = [12]

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First matrix is 1*3 and second is 3*1.
You take the outer two so the answer will be 1*1.
1*1 +3*1+2*3
Answer is 9

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yaa in d second matrix it will b a big 1 single matrix
u solve dis ques in dis way
[1x1+3x1+2x3]
[10]
so 10 is d answer

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[12]
1
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