Math 11, solve for x and express the roots in terms of i

((x+3)/3) + ((x+3)/x) = 2

thanks for any help

Multiply through by the common denominator 3x to get

x(x+3) + 3(x+3) = 6x ---> x^2 + 6x + 9 = 6x ---> x^2 + 9 = 0 ---> x^2= -9 ---> x=+/- 3i.

I think it's x= 18, x= -9... but I could be wrong... what level of math is this?