Landing with a speed of 94.7 m/s, and traveling due south, a jet comes to rest in 995 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.
1. What is its magnitude of acceleration in m/s^2?
2. Possible signs or directions of magnitude?
1. What is its magnitude of acceleration in m/s^2?
2. Possible signs or directions of magnitude?
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inital speed = 94.7m/s
final speed = 0m/s
distance for acceleration = 995m
vf^2 = vi^2 + 2ad
0^2 = 94.7^2 + (2)(a)(995)
a = (-94.7^2)/((2)(995))
a = -4.76m/s^2
the direction of acceleration is north, because the jet is decelerating
final speed = 0m/s
distance for acceleration = 995m
vf^2 = vi^2 + 2ad
0^2 = 94.7^2 + (2)(a)(995)
a = (-94.7^2)/((2)(995))
a = -4.76m/s^2
the direction of acceleration is north, because the jet is decelerating