Physics homework problem, help?!
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Physics homework problem, help?!

[From: ] [author: ] [Date: 12-04-02] [Hit: ]
Possible signs or directions of magnitude?-inital speed = 94.0^2 = 94.a = (-94.a = -4.the direction of acceleration is north,......
Landing with a speed of 94.7 m/s, and traveling due south, a jet comes to rest in 995 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.

1. What is its magnitude of acceleration in m/s^2?
2. Possible signs or directions of magnitude?

-
inital speed = 94.7m/s
final speed = 0m/s
distance for acceleration = 995m

vf^2 = vi^2 + 2ad
0^2 = 94.7^2 + (2)(a)(995)

a = (-94.7^2)/((2)(995))
a = -4.76m/s^2

the direction of acceleration is north, because the jet is decelerating
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