If h(2) = 5 and h'(2) = −9,find
d/dx (h(x)/x) | x = 2.
when i take the derivative of (h(x)/x), i got (xh'(x)-h(x)x') / 2 then i plug in the values given = (2*-9)-(5*0)/ 2^2 and got the final answer of -18/4, but the site i'm doing my hw on says it is wrong, so can anyone tell me what i did wrong or tell me how to do it? thanks so much
d/dx (h(x)/x) | x = 2.
when i take the derivative of (h(x)/x), i got (xh'(x)-h(x)x') / 2 then i plug in the values given = (2*-9)-(5*0)/ 2^2 and got the final answer of -18/4, but the site i'm doing my hw on says it is wrong, so can anyone tell me what i did wrong or tell me how to do it? thanks so much
-
Are you using the quotient rule? Then the derivative of h(x)/x is (xh'(x) - h(x)x')/x^2. You have the wrong denominator. It's supposed to be the square of the original denominator.
Oh, I see you plugged in 2^2, so actually you had that right. Instead, your problem is that you said the derivative of x is 0, when actually it's 1.
Oh, I see you plugged in 2^2, so actually you had that right. Instead, your problem is that you said the derivative of x is 0, when actually it's 1.