For what values of x is g(x) > f(x)

Let f(x) = 5x^2 and g(x) = x^3/5. For what values is g(x) > f(x)?
A) f(x) > g(x) for all values of x
B) g(x) > f(x) for all values of x
c) x > 0
d) x>125
e) x > 25
Please show with steps

x^3/5 > 5x^2
x^3 > 25x^2
x^3 - 25x^2 > 0
x^2 (x-25) > 0

Since x^2 is always >= 0, this will only happen when x-25 > 0, or x>25

The answer is (e), x>25.

Algebra:

g(x) > f(x)
x^3/5 > 5x^2
x^3/5- 5x^2>0
x^2(x/5-5)>0
x>0 and x>25. Chose the more restrictive interval, which is x>25. Answer: e).

Graphing:
Graph x^3/5- 5x^2 and notice that the graph is only positive for x-values greater than 25
https://www.google.com/search?sourceid=c…
Answer: e).