I'm doing this:
pOH= -log .00008 (four zeros)
pOH= - -9.4
pOH= 9.4
But that result is wrong, it should be 4.08. Where I'm wrong?
pOH= -log .00008 (four zeros)
pOH= - -9.4
pOH= 9.4
But that result is wrong, it should be 4.08. Where I'm wrong?
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log base 10 of 0.00008 means 10 raised to what power gives 0.00008
That's just the definition of log.
10^(-4) = 0.0001
10^(-5) = 0.00001
So the true result must be somewhare between -4 and -5.
When I did this with natural log, I got -9.43
Here, you need to use log base 10, not log base e which is ln
pH is measured in terms of base 10.
I think that is where your error is.
That's just the definition of log.
10^(-4) = 0.0001
10^(-5) = 0.00001
So the true result must be somewhare between -4 and -5.
When I did this with natural log, I got -9.43
Here, you need to use log base 10, not log base e which is ln
pH is measured in terms of base 10.
I think that is where your error is.
-
log[10](0.8e-4) = - 4.096910013
ln(0.8e-4) = - 9.433483923
ln(0.8e-4) = - 9.433483923