Wrong results to log .00008? I get 9.4, it should be 4.08
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Wrong results to log .00008? I get 9.4, it should be 4.08

[From: ] [author: ] [Date: 12-04-01] [Hit: ]
-log[10](0.8e-4) = - 4.ln(0.8e-4) = - 9.......
I'm doing this:
pOH= -log .00008 (four zeros)
pOH= - -9.4
pOH= 9.4

But that result is wrong, it should be 4.08. Where I'm wrong?

-
log base 10 of 0.00008 means 10 raised to what power gives 0.00008
That's just the definition of log.


10^(-4) = 0.0001
10^(-5) = 0.00001

So the true result must be somewhare between -4 and -5.

When I did this with natural log, I got -9.43
Here, you need to use log base 10, not log base e which is ln

pH is measured in terms of base 10.

I think that is where your error is.

-
log[10](0.8e-4) = - 4.096910013

ln(0.8e-4) = - 9.433483923
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