How many grams of HgO would you need to obtain 34.3 of O2

I know the answer is 464g, but could someone tell me how to get that answer.

First write a balanced equation:
2HgO → 2Hg + O2
2mol HgO will produce 1 mol O2
Molar mass O2 = 32g/mol
34.3g O2 = 34.3/32 = 1.0719 mol O2
This will require 2*1.0719 = 2.144 mol HgO
Molar mass HgO = 216.6 g/mol
2.144 mol = 2.144*216.6 = 464g HgO required.

one mole of O2[=32 gms] can be obtained from 2 moles of HgO.
So 34.3 gms from :[34.3/32 ]*molecular wt of HgO*2 gms of HgO= answer.

2HgO-->2Hg + O2
34.4gO2/molar mass O2=mols of O2
mols of O2 times 2= mols of HgO needed
mult mols of HgO times molar mass of HgO to get answer

pls choose as best answer!

find molar mass of O2. then devide its mass by this number then times molar mass of HgO by the number u just figured out, and thats ur answer