I know the answer is 464g, but could someone tell me how to get that answer.
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First write a balanced equation:
2HgO → 2Hg + O2
2mol HgO will produce 1 mol O2
Molar mass O2 = 32g/mol
34.3g O2 = 34.3/32 = 1.0719 mol O2
This will require 2*1.0719 = 2.144 mol HgO
Molar mass HgO = 216.6 g/mol
2.144 mol = 2.144*216.6 = 464g HgO required.
2HgO → 2Hg + O2
2mol HgO will produce 1 mol O2
Molar mass O2 = 32g/mol
34.3g O2 = 34.3/32 = 1.0719 mol O2
This will require 2*1.0719 = 2.144 mol HgO
Molar mass HgO = 216.6 g/mol
2.144 mol = 2.144*216.6 = 464g HgO required.
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one mole of O2[=32 gms] can be obtained from 2 moles of HgO.
So 34.3 gms from :[34.3/32 ]*molecular wt of HgO*2 gms of HgO= answer.
So 34.3 gms from :[34.3/32 ]*molecular wt of HgO*2 gms of HgO= answer.
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2HgO-->2Hg + O2
34.4gO2/molar mass O2=mols of O2
mols of O2 times 2= mols of HgO needed
mult mols of HgO times molar mass of HgO to get answer
pls choose as best answer!
34.4gO2/molar mass O2=mols of O2
mols of O2 times 2= mols of HgO needed
mult mols of HgO times molar mass of HgO to get answer
pls choose as best answer!
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find molar mass of O2. then devide its mass by this number then times molar mass of HgO by the number u just figured out, and thats ur answer