Professor got all into lottery probability this week with Mega Millions going on. He asked what is the probability of not drawing a specific ball 10 games in a row? With a 56 balls lottery excluding Mega Ball.
I believe it is [(55/56)(54/55)(53/54)(52/53)(51/52)]^10 = .392484 (39.25%) but I am unsure of its validity. Please help.
I believe it is [(55/56)(54/55)(53/54)(52/53)(51/52)]^10 = .392484 (39.25%) but I am unsure of its validity. Please help.
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in each of 10 games, all 56 #s become available, so
Pr = (55/56)^10 =.8351 <--------
your AD
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i thought only 1 ball was being considered.
ok, 5 balls are being drawn, but for each of 10 draws, only 55 balls are "permissible" to be drawn, so (using another method)
Pr = (55c5/56c5)^10 = (51/56)^10 = .39248 <--------
your ans is correct !
Pr = (55/56)^10 =.8351 <--------
your AD
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i thought only 1 ball was being considered.
ok, 5 balls are being drawn, but for each of 10 draws, only 55 balls are "permissible" to be drawn, so (using another method)
Pr = (55c5/56c5)^10 = (51/56)^10 = .39248 <--------
your ans is correct !
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2 multiples by 2 is the answer.