Find the derivative with respect to x

1) y = (3x^2 - 2 )^4
2) y= 2x^3(3x + 7 )^5

answers
1) 24x(3x^2 - 2)^3
2) 6x^2(8x + 7)(3x + 7)^4

y = (3x^2 - 2 )^4 = u^4 where u = 3x^2 - 2
using the chain rule y' = dy/du * du/dx = 4u^3 * 6x = 4 (3x^2 - 2)^3 * 6x = 24x(3x^2 - 2)^3

y= 2x^3(3x + 7 )^5 = 2x^3 * u^5 where u = 3x + 7
using the chain rule and the product rule,
y' = 2x^3 * 5u^4 *3 + (3x + 7 )^5 * 6x^2 = 2x^3 * 5(3x + 7)^4 *3 + (3x + 7 )^5 * 6x^2