Help needed with Trig problem?!

(1/3)^(4x-1)=3^(x-1)

I think I have to use logs to solve but I'm not sure where to put everything
Answers appreciated

You don't need to use logs because your bases are already the same. Thus, you just equate your indices.

(1/3)^(4x-1)=3^(x-1)
(3^-1)^(4x-1) = 3^(x-1)
.:. -1(4x-1) = x-1
1 - 4x = x - 1
5x = 1
x = 1/5